How to declare a function throws an error in TypeScript
- Admin
- Mar 6, 2024
- Typescript
In programming, handling errors is a common necessity to maintain code integrity.
It is the responsibility of a programmer to handle errors effectively, ensuring clean code and preventing the premature termination of an application.
While TypeScript’s compiler aids in catching compile-time errors with its type safety features, handling runtime errors requires a different approach.
How can you manage runtime errors in TypeScript?
TypeScript provides an Error
object to signify the occurrence of an error during runtime.
In TypeScript, the Error
object represents a runtime exception or error. Additionally, TypeScript supports the never type, which accommodates any type of data.
In TypeScript, error handling is typically done using the try and catch blocks:
try {
throw new Error("An error occurred.");
} catch (e) {
console.log(e.message);
}
How do you declare a function that throws an Error?
Unlike some other programming languages, declaring a function explicitly as throwing an error is not directly supported in TypeScript.
With the current version of TypeScript (4.3.x), the following syntax is invalid:
function myFunction(param: string): throws Error {
}
Instead, you can achieve similar functionality using the never
type and the union
operator:
function myFunction(test: string): string | never {
if (!test) {
throw new Error("Test failed.");
}
return test;
}
The above function has the potential to throw an error or return a string. You can combine the never
type with other types like boolean
or number
using the union
pipe operator.